imp/celeste/attacks/paddingoracle.py

106 lines
3.9 KiB
Python

from math import inf, ceil
from typing import Callable
from celeste.math.util import clamp_max
SPACER = b'\xff' # arbitrary spacing character
class DecryptFailed(Exception):
pass
def round_to_blocks(n: int, block_size: int) -> int:
return ceil(n / block_size)
def crack_secret_len(cipher: Callable[[str], str],
max_iters: int = inf) -> int | None:
# calculate length for i = 1
init_len = len(cipher(SPACER))
secret_len = None
i = 2
while True:
if i - 2 > max_iters:
break
elif len(cipher(SPACER*i)) != init_len:
secret_len = init_len - i
break
i += 1
return secret_len
'''
NOTE: pad_if_perfect exists for PKCS#7 which will add a full block
NOTE: of padding if the input is perfectly alligned to the blocks already.
'''
def crack(cipher: Callable[[str], str],
padfn: Callable[[bytes, int], bytes],
charset: list,
block_size: int,
max_secret_iters: int = inf,
batch_size: int = 1,
pad_if_perfect: bool = True,
debug: bool = False) -> str | None:
if len(charset) % batch_size:
raise ValueError(f'batch_size={batch_size} does not divide len(charset)={len(charset)}')
# calculate the secret length
secret_len = crack_secret_len(cipher, max_iters=max_secret_iters)
if debug:
print(f'[+] Found secret length: {secret_len}')
# calculate how many blocks the secret stretches over
# NOTE: secret_block_len - secret_len represents the number of
# NOTE: bytes required to make the secret fill the blocks with no padding
secret_block_len = round_to_blocks(secret_len, block_size) * block_size
default_push = (secret_block_len - secret_len)
known = b''
while True:
# the "full tail" is all characters we know + the 1 we're cracking (target)
# the "current tail" is the characters in the same block as the target
full_tail_bytes = len(known) + 1
tail_bytes = clamp_max(full_tail_bytes, block_size - 1)
# generate ALL possible tails (avoid padding if no padding required)
tails = [c + known[:tail_bytes] for c in charset]
if len(tails[0]) != block_size:
tails = [padfn(tail, 16) for tail in tails]
# calculate the "push" applied to the secret
push_size = (default_push + full_tail_bytes) % block_size
matched = False
NUM_BATCHES = len(tails) // batch_size
for i in range(NUM_BATCHES):
if debug:
print(f'{int(i/NUM_BATCHES*100)}%', end='\r')
batch = tails[i*batch_size : (i+1)*batch_size]
batch = b''.join(batch) + (SPACER * push_size) # apply spacing
# encrypt batch and split the ciphertext into blocks
ciphertext = cipher(batch)
num_blocks = len(ciphertext)//block_size
blocks = [ciphertext[i*block_size : (i+1)*block_size] for i in range(num_blocks)]
oracle_pos = round_to_blocks(full_tail_bytes, block_size)
if pad_if_perfect and (push_size + secret_len) % block_size == 0:
oracle_pos += 1
for j, cipher_block in enumerate(blocks[:batch_size]):
if cipher_block == blocks[-oracle_pos]:
char = charset[i*batch_size + j]
known = char + known
if debug:
print(f'[*] Found Tail: {known}')
matched = True
break
if matched:
break
if not matched:
break
elif len(known) == secret_len:
if debug:
print('[+] SUCCESS')
return known
# if we reached the end (no return)
# then the attack failed
err_msg = 'Padding oracle attack failed'
if not debug:
raise DecryptFailed(err_msg)
print(f'\n[!] {err_msg}')