'''
The unchanged original "bcrypt" function for the CTF (by bpaul)
'''
def bcrypt(x: bytes) -> int:
    h = 18446744073709551614

    for (i, b) in enumerate(x):
        h *= h * (b + 1)
        k = 59275109328752 * (i + 1)
        for j in range(8):
            k ^= b << (j * j)
        h += k
        h %= (2 ** 64)

    return h